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2 votes

Baseband downconversion without imaging

@moltarze Still you did not implement down conversion correctly, I think. Let $x[n] = x_r[n] + ix_i[n]$ be the input signal to be down-converted by the carrier $$c[n] = e^{-in\text{arg}} = \cos(n\...
AHT's user avatar
  • 379
1 vote

Baseband downconversion without imaging

Keep in mind that multiplying an input time-domain signal by a cosine wave (or a sine wave) is "modulation" and NOT "frequency translation." To implement frequency translation you ...
Richard Lyons's user avatar
0 votes

How do you interpret the sign (positive, negative or zero) of the phase spectrum?

The phase response in both cases represents the relative phase shift within the window you are looking at. For the DFT, this represents the phase shift of one sinusoidal component relative to a ...
Baddioes's user avatar
  • 1,040
2 votes

How do you interpret the sign (positive, negative or zero) of the phase spectrum?

The best way to view the phase of a digital filter that operates in real-time is, first represent a polarity inversion, that is that the linear gain at (or very close to) DC is negative, as a phase ...
robert bristow-johnson's user avatar

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