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Your "instantaneous voltage of AM wave" is a product of carrier and modulation waves decomposed into a sum of pure trig functions. Let us write down this product in its original form: $$e_{AM} = E_c·cos(\omega_c t) · (1 + m·cos(\omega_s t))$$ where angular frequency ω = 2πf. A Fourier transform of this "voltage of AM wave" is  \sqrt{\...

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Regarding your problem it seems that there is a misunderstanding between dB and dBm. When we talk about the power ratios between signals we will express the difference in dB while when we will express the power of the signal we will be interested in the power in dBm which is none other than the power of the signal in question compared to 1mW. Which leads me ...

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Are you familiar with how to obtain the Fourier series of an arbitrary periodic function? Because if you are, I'm confused at your confusion. This is simply the Fourier series expansion of the triangle wave with fundamental frequency $f_0=1/T$. This can be found by taking the inner product of the function with the basis functions. We note that the DC value (...

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