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1 vote

Overcoming the negative instantaneous frequencies from Hilbert transform

I tried to reproduce the paper you attached to get the corrected Instantaneous Phase and Frequency. So as far as I understood, the velocity vector is the derivation of the analytical signal, so here ...
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0 votes

Instantaneous frequency vs time for a piecewise signal

Measurements of instantaneous frequency are highly susceptible to noise given the derivative operation which is a high pass filter. The results ultimately for a signal with noise present (as it ...
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0 votes

How do I convert a sampled complex signal to a real signal?

Let us assume a baseband complex sampled noisy signal with a power spectrum as depicted below: The signal spectrum is depicted with a notch to emphasize that it is complex and therefore not conjugate ...
3 votes
Accepted

Does the Kramer-Kronig relations apply to this example $f(t) =\left(1-t^2\right)^4\cdot\theta(1-t^2)$?

The function $f(t)$ is real-valued and even, and so is its Fourier transform $F(\omega)$. Clearly, the real and imaginary parts (the latter being zero) of $F(\omega)$ are not related via the Hilbert ...
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3 votes
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Can we find the RMS of a signal from its envelope?

Given a real signal $x(t)$, its complex analytic signal $x_a(t)$, and the envelope as the absolute magnitude of the analytic signal: $|x_a(t)|$, we can relate the RMS of the envelope to the RMS of the ...
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0 votes

Converting real samples to IQ

Okay, you have two different symbols, $n$ and $t$, representing the same thing. I am going to define $t=nT$ (where $T$ is the sampling period for $x(t)$ and $x[n]\triangleq x(nT)$ ). Method 1: ($\...
2 votes
Accepted

Converting real samples to IQ

Note the OP has mixed continuous time and discrete time formulations. My answer below is given with continuous time $t$ but can equally be applied to discrete time index $n$. A real signal cannot ...
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