# Tag Info

### How can we measure the accuracy of channel estimation?

I'm not sure how much of the receiver for this signal you have implemented but if you are actually able to demodulate data into a constellation then why not use the error vector magnitude (https://en....
Accepted

### which type of diversity is used by rake receivers?

I just received this email from one of the greatest in wireless communications: Dr. Fuyun Ling. He said: "I think the confusion point is what is the definition of the (optimal) frequency or time ...
• 85

### which type of diversity is used by rake receivers?

If it's the rake receiver scheme that I'm familiar with, it's a spread-spectrum signal using a pseudo-random code, and finding multiple correlation peaks in the received signal (which, if you plot it ...
• 10.7k
1 vote

### which type of diversity is used by rake receivers?

Personally, I think it's more natural to describe the RAKE receiver as a time-diversity system. However, in a wireless system multipath is only resolvable if the bandwidth is large, so RAKE receivers ...
• 14.1k

### Learning transceiver algorithms

As Marcus points out, the answer depends on what you mean by "basic". It also depends on whether you already know the math and want to focus on implementations. If you know how to code, and ...
• 14.1k

### Choosing the scaling parameters for a modem implementation

The optimum solution for where to set the Automatic Gain Control (AGC) relative to the full scale of the ADC typically allows for some clipping given the goal is to minimize the total noise ...
• 41.1k

### Understanding the signal to noise ratio (SNR)

Typically signal to noise ratio is quoted over a time average. Remember that \begin{align} \textbf{u}(n) \end{align} is additive white noise. This means that the values $\textbf{u}(n)$ are random ...
• 57
As Hilmar points out in a comment, the answer depends on whether the baseband signal is real or complex. Consider a real baseband signal $r(t)$ with bandwidth $B$. It must be sampled at rate $2B$. ...