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3 votes

Why is sampling not “idempotent”?

Here is what I think is a nice pictoral way to think through this question. Sadly there is signal processing literature out there that does equate multiplication by a Dirac comb with sampling. But ...
Georg Essl's user avatar
3 votes

Why is sampling not “idempotent”?

Sampling” actually means multiplying by a Dirac comb No. Sampling means turning a continuous function into a discrete set of numbers, so the process is simply $$x[n] = x(nT_\mathrm{s})$$ where $T_\...
Hilmar's user avatar
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1 vote

Why is sampling not “idempotent”?

The problem here is the mathematical model you're using. In practice there is no such thing as a Dirac comb. For some mathematical manipulations, the model of multiplying a continuous-time function ...
Matt L.'s user avatar
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0 votes

Why is sampling not “idempotent”?

While viewing sampling from the perspective of a dirac comb is correct and can be helpful, I find it is not the most complete or rigorous description of sampling. Sampling is best viewed, in my ...
Baddioes's user avatar
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