New answers tagged state-space
3
Model your deterministic input as a $2 \times 1$ matrix :
$$ \begin{bmatrix}
u \\
T_a \\
\end{bmatrix}
$$
Then your state space equations will be:
$$ \begin{bmatrix} \dot x_1 \\ \dot x_2 \\ \dot x_3 \end{bmatrix} = \begin{bmatrix}
-\frac 13p & \frac 13p & 0 \\
p & -(p+ \frac{c}{10}) & \frac{c}{10} \\
0 & \frac{c}{30} & -(\...
1
Probably not much advantage either way, possibly unless you've got a really high-order modulator (in which case someone else will have to answer!)
If the state-space representation is a single-input single-output system, and if it's linear, and if it's running in steady-state, and if data path widths aren't an issue, then there's no difference between it ...
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