# How do you find the phase of the DFT of a discrete signal?

My question is similar to this one and this one, but neither answers address my concern.

Suppose you have a signal x(n) = {-1,2,-3,2,-1} where we can assume x(0) = -3. So this is an even signal.

How do you find the phase of the DFT of x(n)?

• What you show is not an even signal, did you mean x(n) = {1,2,-3,2,1}? Mar 21 '20 at 3:28
• This post should help you: dsp.stackexchange.com/questions/38544/… Mar 21 '20 at 3:29
• Sorry my mistake. Now it's even Mar 21 '20 at 3:30
• @DanBoschen - I am not sure I see which part of the post is relevant to this question. So the answer to this question is $\pi$, but I'm not sure I see why. Mar 21 '20 at 3:33
• No problem, this was very helpful Mar 21 '20 at 3:51

$$x(n) = [-1,2,-3,2,-1]$$
$$x(n) = [-3, 2, -1,-1, 2]$$