My question is similar to this one and this one, but neither answers address my concern.
Suppose you have a signal x(n) = {-1,2,-3,2,-1} where we can assume x(0) = -3. So this is an even signal.
How do you find the phase of the DFT of x(n)?
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Sign up to join this communityMy question is similar to this one and this one, but neither answers address my concern.
Suppose you have a signal x(n) = {-1,2,-3,2,-1} where we can assume x(0) = -3. So this is an even signal.
How do you find the phase of the DFT of x(n)?
Here is a hint that will help you:
The DFT is cyclical in time and in frequency. For the sequence given by
$$x(n) = [-1,2,-3,2,-1]$$
With x(0) = -3 would be solved using the standard DFT equation that starts at n=0 using
$$x(n) = [-3, 2, -1,-1, 2]$$
From that you can solve for the DFT and then determine easily for each result what it's phase is.