I wanted to understand better how zero padding affects a signal: Which is just N ones. where $ N > 0$ is an Integer $$ X[n] = 1, 1, 1, ... 1 $$ Zero padding it gives: $$ X[n] = 1, 1, 1, ... 1, 0, 0, 0, .. 0 $$ Which is N ones, and K zeros.
I know that Changing the Length of the signal by adding K zeros gives us a different $\omega = \frac{2\pi}{N}$ because N Is different.
When I calculate the Fourier Transform I get:
$\Large \hat X = \frac{1 - e^{-i\omega N}}{ 1 - e^{-i\omega}}$
And I don't understand how it affects the Fourier transform when I plot it on the $\omega $ scale.