Nyquist's formula for maximum channel capacity (noiseless channel): $C=2B \log_2(M)$
Shannon's formula (noisy channel): $C=B \log(1+S/N)$.
- I need to distinguish between the symbol rate and the bit rate.
- Ragarding the symbol rate, do the two formulas says that one cycle of a signal (i.e 1 Hz) cannot carry no more than 2 symbol/cycle?
- Regarding the bit rate, Nyquist formula doesn't put a limit on the number of bits that can be put in each symbol, while Shannon formula takes that consideration.
Is my understanding correct?