2
votes
How to perform Spatial derivative calculation?
What you should do instead to calculate $I_x$:
$$
\begin{align}
I_{x}(x,y)&=\frac{\partial I(x,y)}{\partial x}\\
&=I(x+1,y)-I(x-1,y)\\
&=
\begin{bmatrix}5& 7 & 11\\
9 & 12 &...
- 26k
1
vote
Accepted
Harris Corners Detector squared derivatives
I think this part in article is starting point of the confusion :
See how the $I(x+u, y+v)$ changed into a totally different form
$I(x,y)+ uI_x + vI_y)$?
The author should have write a bit more ...
- 1,976
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