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2 votes

How to perform Spatial derivative calculation?

What you should do instead to calculate $I_x$: $$ \begin{align} I_{x}(x,y)&=\frac{\partial I(x,y)}{\partial x}\\ &=I(x+1,y)-I(x-1,y)\\ &= \begin{bmatrix}5& 7 & 11\\ 9 & 12 &...
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1 vote

Harris Corners Detector squared derivatives

I think this part in article is starting point of the confusion : See how the $I(x+u, y+v)$ changed into a totally different form $I(x,y)+ uI_x + vI_y)$? The author should have write a bit more ...
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