In discrete Kalman Filter, we assume the measurement noise is "white". ... Can we realistically assume that in continuous filter? When the time between measurements is so small, there have to be some correlation?
The noise doesn't have to be completely white -- it just needs to be flat enough and wideband enough that there's nothing to be gained by modeling it as colored.
For a steady-state Kalman, as long as the noise bandwidth ends up being at least four times faster than the dynamics of the filter. If you need to know whether it matters in those first few moments as the filter is spinning up, that's a separate question*.
Why the smaller the $\Delta t$ is, the bigger the measurement noise is?
I asked just that question the first time I saw that in a textbook (Optimal State Estimation by Simon, in my case).
If the textbook that the lecture refers to uses the same technique, it's because the author assumes an integrating system, and then finds the measurement noise that has the same result.
Note that this result probably isn't true for a different starting system -- I'm not sure why the authors don't start by just saying "c'mon, it's different because it's continuous-time". But they don't. Personally, if I were doing a continuous-time Kalman, I'd use the (hopefully) known spectral density of the process and measurement noise for $\mathbf Q$ and $\mathbf R$, rather than messing around with discrete-time counterparts.
* And one I'd have to work to answer, either by doing some math or finding some papers. I think the first approach I'd take would be to model the system with colored noise, then compare the performance of a Kalman that also models that colored noise vs. one that pretends that the noise is white. That may not give a general result, but it would at least answer the question for a specific system.