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I tried to call decimate function in Scipy from Matlab but met an error. Can somebody point me in a direction, please?

Here is a code of Matlab

py.print("Hello, Python!")
% generate a sin signal
clear
fc=2;  % in Hz
f_sampling=100;   %in Hz
t=0:1/f_sampling:3;  %in 3s
y=sin(2*pi*fc.*t);   % signal
plot(t,y)
y_dem=py.scipy.signal.decimate(y,5); 

>> try_python
Hello, Python!
Error using signaltools>decimate (line 4401)
Python Error: TypeError: 'float' object cannot be interpreted as an integer
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    $\begingroup$ Code did not show line by line. Retype it for easy reading $\endgroup$
    – Jingdong Zhang
    Commented May 7 at 14:39
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    $\begingroup$ fc=2; % in Hz f_sampling=100; %in Hz t=0:1/f_sampling:3; %in 7ms y=sin(2*pi*fc.*t); % signal $\endgroup$
    – Jingdong Zhang
    Commented May 7 at 14:41
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    $\begingroup$ sorry, I am not able make it line by line $\endgroup$
    – Jingdong Zhang
    Commented May 7 at 14:42
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    $\begingroup$ You can use the {} button to format text as code. Hover over the buttons and they tell you what they do $\endgroup$
    – Hilmar
    Commented May 7 at 15:01
  • $\begingroup$ Thank you, Hilmar $\endgroup$
    – Jingdong Zhang
    Commented May 7 at 16:10

1 Answer 1

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Matlab uses double values by default. Scipy.signal.decimate expects an integer as the second argument, the decimation factor.

Explicitly convert your decimation factor to an integer type:

y_dem=py.scipy.signal.decimate(y,int32(5));
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  • $\begingroup$ Hi Jdip. It works. Thank you very much for your quick reply. $\endgroup$
    – Jingdong Zhang
    Commented May 7 at 16:07

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