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How are these two signals equal?

What I have tried:

$ x[n] = (-3)(-2)(-2)^{n-1}u[n] + (-2)^{n-1}u[n] $

I am not sure how this leads to the answer.


They are indeed equal. The first term is


The value of $(1)$ at $n=0$ is $6/(-2)=-3$, so we can rewrite it as


Adding the second term $(-2)^{n-1}u[n-1]$ results in



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