0
$\begingroup$

I have a series of numbers. They may be integer, floating, or binary. Length of series is constant. I need criteria which is circle shift invariant. For more information assume series S1, S2, S3, S4 and S5:

S1 = {A, B, C, D, E, F}
S2 = {F, A, B, C, D, E}
S3 = {D, E, F, A, B, C}
S4 = {A, C, D, F, E, B}
S5 = {A, B, C, D, E, G}

where A, B, C, E, F, and G are numbers. S2 and S3 is resulted by shift circle of S1. So the criteria should return same values for these three series. S4 have same number of S1, S2, and S3 but order of numbers are not the same. S5 and S1 are similar so I want to criteria of S1 and S5 be similar.

I want to use them as descriptors in image processing. In other words, I want to make a feature (like LBP, or HOG) rotation invariant. For example mean and variance can be used but I need more. Are there any suggestion?

$\endgroup$
2
  • $\begingroup$ So what is your problem /question? You are describing the situation, and mentioning something about criteria, but it is unclear what you want to achieve and why you are not able to do this? $\endgroup$ Commented Jun 6, 2018 at 10:47
  • $\begingroup$ I need criteria for these series for comparing them as I said. These criteria should be circle shift invariant. $\endgroup$
    – Babak.Abad
    Commented Jun 6, 2018 at 11:18

1 Answer 1

1
$\begingroup$

A possible way to approach the problem would be to extract the maximum values of the discrete circular convolution of each pre-normalized sequence with an NXN matrix formed by the elements of an orthonormal base of the Nx1 sequence space.

The output of this step would be a Nx1 vector that would contain a measure of the similitude of each sequence with the each base sequence. If base sequences are adequately chosen, similar sequences should have similar output vectors, and an operator like mean square difference between outputs should tell how similar are two input sequences.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.