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If we have an Image I and a Gabor filter created at specific size and orientation, assume that is 11x11.

I saw some persons who normalize the size of the filter, but i didn't understand what was meant by "precalculate the normalization of the filter size". And within the normalization, they square the image, for example : Isquare = I^2. So why the image is squared ?

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Each pixel of the filter has a magnitude (intensity). The square function equivalently calculate the power density of the pixel. The normalization is to scale the filter power to 1. That's where I^2 at the denominator comes from.

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Normally, ,,normalization'' means to make the L2 norm (sum of squares) of a signal $1$. This is usually achieved by calculating the inverse of the sum of squares and multiplying by it.

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  • $\begingroup$ Sorry but i didn't understand well what do you mean. What was meant by "sum of squares" ? and why the image is squared ? please can you edit your response to include more explanation :) thank's in advance! $\endgroup$ – Christina Dec 28 '13 at 13:53

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