Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options not deleted user 70361
1 vote
1 answer
53 views

Communication Channel under Doppler effect

the total received signal of $A$ at discrete time is $\mathbf{y}_A [n] = \mathbf{x}_A[n - \tau]e^{j 2 \pi n f_D} + (\mathbf{h}_{BA} \ast \mathbf{x}_B)[n],$ where $\tau$ and $f_D$ are the time delay and Doppler … I am confused at the channel tap $\mathbf{h}_{BA}$ whether it can capture the Doppler effect or not because the target B is moving. I appreciate all of your help. …
Rayzain's user avatar
  • 37