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Communication Channel under Doppler effect
the total received signal of $A$ at discrete time is
$\mathbf{y}_A [n] = \mathbf{x}_A[n - \tau]e^{j 2 \pi n f_D} + (\mathbf{h}_{BA} \ast \mathbf{x}_B)[n],$
where $\tau$ and $f_D$ are the time delay and Doppler … I am confused at the channel tap $\mathbf{h}_{BA}$ whether it can capture the Doppler effect or not because the target B is moving.
I appreciate all of your help. …