So I was following this article: https://www.docdroid.net/YSKkZ5Y/fft-based-2d-cyclic-convolution-pdf#page=7

I have expanded the kernel to the correct way they have done it. However when it comes to the part on clamping to the edge its very confusing. I would love for someone to explain this as i require the image convolved as the same shape before the padding, but in this article it just shows how to convolve with clamp to edge but not how to recover it.

code as of now

def circExt(k, rows, cols):
    radiusV = np.floor(k.shape[0] / 2)
    radiusH = np.floor(k.shape[1] / 2)
  
    k_c = k

    k_c = np.pad(k_c,((0, int(rows-k.shape[0])), (0, int(cols-k.shape[1]))))

    k_c = np.roll(k_c, int(-radiusV), axis = 0)
    k_c = np.roll(k_c, int(-radiusH), axis = 1)
    
    return k_c
    

def testfft2(image, kernel):
    imageC = image.copy()
    kSize = (kernel.size // 2) + 1
    kernelShape = tuple(ti//2 for ti in kernel.shape)
    
    k_width = kernel.shape[1]
    k_height = kernel.shape[0]
    
    centery ,centerx = kernelShape
    
    imageC = np.pad(imageC, ((0, int(centery)), (0, int(centerx))) , mode = "edge")

    imageC = np.pad(imageC,((0, int(k_height-centery-1)), (0, int(k_width-centerx-1))), mode = "wrap" )

    kernelShift = circExt(kernel, imageC.shape[0], imageC.shape[1])   

    imageC = np.fft.fft2(imageC)
    kernel= np.fft.fft2(kernelShift)
    output = np.real(np.fft.ifft2(np.multiply(imageC, kernel)))

    return output
```