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I am a little bit confused about the concept of sampling rate conversion. Consider the following question:

Wideband telephony signals are sampled at a sampling frequency fS1 = 16kHz. To process these signals with an automatic speech recognizer, the sampling rate is converted here to fS2 = 11.025kHz, i.e., the wideband signal is first upsampled by a factor U, lowpassfiltered, and finally downsampled by a factor R. Determine the lowest possible values for R and U.

I am not sure whether U / R = 16kHz / 11.025 kHz, or vice-versa?

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You would upsample by 441 and downsample by 640 since $11025 \cdot 640 = 16000 \cdot 441$

That would be a rather expensive operation, so in practice you would either fugde it a bit: 31/45 would get you to 11022Hz and 11/16 to 11000 Hz or you would use a suitable poly-phase irrational conversion algorithm

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  • $\begingroup$ Thanks. I am confused, because I thought since we're going from 16k to 11.025k, it means that we will have more sample (in time-domain?!), so we should upsample by a factor of 640 and downsample by 441. $\endgroup$
    – Niousha
    Commented Mar 27, 2019 at 21:23
  • $\begingroup$ i dunno that i would associate polyphase with "irrational" ratios of sample rates. maybe polyphase with a lot of phases and linear interpolation for arbitrary conversion ratios. $\endgroup$
    – robert bristow-johnson
    Commented Mar 27, 2019 at 21:30

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