I have question and looking for help. Suppose we have a vector of real values (lat's say 64 length resulting from factorization 8*8 block image). We got a sparse representation of that vector (let's suppose that the sparse vector is 128 length with very few active elements, about 4 coefficients). I want to send this sparse vector through a channel, so I need bit stream of 1,0. Are there any efficient encoding/decoding technique for the sparse signals ?
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$\begingroup$ Since you have all sample, I think you are better to avoid compressive sampling, it is for efficeint sampling not coding.decoding. For signal compression, there are tones of compression algorithms, like LRZ,Huffman,... $\endgroup$– MimSaadCommented Aug 13, 2016 at 13:06
1 Answer
Since you have tagged your question compressive-sensing, I would guess that you are interested in a compressive sensing solution to this. In principle, this could work by taking a number (less than 64) of random linear combinations (measurements) of your length 64 vector and transmitting these. At the receiver, the fact that this vector has a sparse representation allows you to reconstruct it again from these measurements. However, compressive sensing does not work that well on low-dimensional vectors (64 is relatively small) and so I do not expect this scheme to work very well.
A more natural solution, since you mention that you know the sparse length 128 representation of the vector, is to use run-length encoding (Wikipedia explanation) of the sparse representation and transmit that. Since the sparse vector is almost all zeros, this should be very efficient.
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$\begingroup$ Well, if I understood correctly, you are saying that we can take some measurements and transmit them and at the receiver side we get the original signal from the sparse version . Instead why not we send the sparse version and the receiver get the original signal from the sparse version directly? I know the sparse signal is longer but the active elements on it is very limited, does that point make sense? $\endgroup$– RashwanCommented Apr 18, 2016 at 16:19