As far as I have grasped the concept,

$$ y[n] = \left( 2 x[n] - x^2[n] \right)^2 $$

is a memoryless system because even if we give negative values of $n$, we still get the overall result in the positive sign, right?

And the following expression is memoryful system because we get the negative answer for negative values of $n$, right?

$$y[n] = \left( 2 x[n] - x^2[n] \right)$$

As far as I have grasped the concept,

$$ y[n] = \left( 2 x[n] - x^2[n] \right)^2 $$

is a memoryless system because even if we give negative values of $n$, we still get the overall result in the positive sign, right?

And the following expression is memorable system because we get the negative answer for negative values of $n$, right?

$$y[n] = \left( 2 x[n] - x^2[n] \right)$$

As far as I have grasped the concept is that if we are given the expression

$$y[n]=(2x[n]-x^2[n])^2\,,$$

it is a memory less system because even if we give negative values of $n$, we still get the overall result in the positive sign, right?

And this expression is memory system because we get the negative answer for negative values of $n$, right?

$$y[n]=(2x[n]-x^2[n])\,.$$

As far as I have grasped the concept,

$$ y[n] = \left( 2 x[n] - x^2[n] \right)^2 $$

is a memoryless system because even if we give negative values of $n$, we still get the overall result in the positive sign, right?

And the following expression is memoryful system because we get the negative answer for negative values of $n$, right?

$$y[n] = \left( 2 x[n] - x^2[n] \right)$$

As far as I have grasped the concept is that if we are given the expression

$y(n)=(2x[n]-x^2[n])^2$

it is a memory less system because even if we give negative values of $n$, we still get the overall result in the positive sign, right?

And this expression is memory system because we get the negative answer for negative values of $n$, right?

$y(n)=(2x[n]-x^2[n])$

As far as I have grasped the concept is that if we are given the expression

$$y[n]=(2x[n]-x^2[n])^2\,,$$

it is a memory less system because even if we give negative values of $n$, we still get the overall result in the positive sign, right?

And this expression is memory system because we get the negative answer for negative values of $n$, right?

$$y[n]=(2x[n]-x^2[n])\,.$$