Skip to main content
edited tags
Link
Matt L.
  • 92.4k
  • 10
  • 81
  • 184
edited title
Link
Matt L.
  • 92.4k
  • 10
  • 81
  • 184

Sampling thorem: convolution Convolution in frequency domain (complex math question)

added 1 character in body
Source Link
Dole
  • 348
  • 1
  • 17

Simple math question. The convolution theorem states that multiplication in time domain is equal to convolution in frequency domain and vice versa. There is a condition that the signal has to be properly zero padded as to not cause aliasing.

This question concerns convolution in the frequency domain. The difficulty comesarises from the fact that we are dealing with a complex signal which has a positive and a negative side. Let's consider two frequency domain signals, with negative frequencies included, presented in polar coordinates []:

a=[0,1(3π/4),0,1(π/2),0)]
b=[1,1,1,1,1]

So we have a sine wave and a zero-phase dirac delta. It's apparent that the time domain product is zero. But coming to this conclusion via using convolution in frequency domain doesn't seem to be so simple. I get (rectangular):

[-j,-j,-j,-j, 0,j,j,j,j,j]
=> [-2j,-2j,0,2j,2j]

Which is not correct. Even for a cosine I get a row of twos, which is not correct either (should be row of ones). Where am I going wrong?

Simple math question. The convolution theorem states that multiplication in time domain is equal to convolution in frequency domain and vice versa. There is a condition that the signal has to be properly zero padded as to not cause aliasing.

This question concerns convolution in the frequency domain. The difficulty comes from the fact that we are dealing with a complex signal which has a positive and a negative side. Let's consider two frequency domain signals, with negative frequencies included, presented in polar coordinates []:

a=[0,1(3π/4),0,1(π/2),0)]
b=[1,1,1,1,1]

So we have a sine wave and a zero-phase dirac delta. It's apparent that the time domain product is zero. But coming to this conclusion via using convolution in frequency domain doesn't seem to be so simple. I get (rectangular):

[-j,-j,-j,-j, 0,j,j,j,j,j]
=> [-2j,-2j,0,2j,2j]

Which is not correct. Even for a cosine I get a row of twos, which is not correct either (should be row of ones). Where am I going wrong?

Simple math question. The convolution theorem states that multiplication in time domain is equal to convolution in frequency domain and vice versa. There is a condition that the signal has to be properly zero padded as to not cause aliasing.

This question concerns convolution in the frequency domain. The difficulty arises from the fact that we are dealing with a complex signal which has a positive and a negative side. Let's consider two frequency domain signals, with negative frequencies included, presented in polar coordinates []:

a=[0,1(3π/4),0,1(π/2),0)]
b=[1,1,1,1,1]

So we have a sine wave and a zero-phase dirac delta. It's apparent that the time domain product is zero. But coming to this conclusion via using convolution in frequency domain doesn't seem to be so simple. I get (rectangular):

[-j,-j,-j,-j, 0,j,j,j,j,j]
=> [-2j,-2j,0,2j,2j]

Which is not correct. Even for a cosine I get a row of twos, which is not correct either (should be row of ones). Where am I going wrong?

Source Link
Dole
  • 348
  • 1
  • 17
Loading