How can I find the Fourier transform of

$$ f(x) = ( \cos(x) )^3$$

I know that for $ g(x) = \cos(x) $

$$ F \Big\{ g(x) \Big\} = F \Big\{ \cos(x) \Big\} = \pi \Big [ \delta(w-\pi / 2) + \delta(w+\pi / 2) \Big ]$$

But using this pair of Fourier transform how to obtain the $ F \Big\{ f(x) \Big\} $ ?? Is there a direct/simple way to do that?

How can I find the Fourier transform of

$$ f(x) = ( \cos(x) )^3$$

I know that for $ g(x) = \cos(x) $

$$\mathcal F \Big\{ g(x) \Big\} = \mathcal F \Big\{ \cos(x) \Big\} = \pi \Big [ \delta(w-\pi / 2) + \delta(w+\pi / 2) \Big ]$$

But using this pair of Fourier transform how to obtain the $ F \Big\{ f(x) \Big\} $ ?? Is there a direct/simple way to do that?

How can I find the Fourier transform of

$$ f(x) = ( \cos(x) )^3$$

I know that for $ g(x) = \cos(x) $

$$ F \Big\{ g(x) \Big\} = F \Big\{ \cos(x) \Big\} = \pi \Big [ \delta(w+\pi / 2) + \delta(w+\pi / 2) \Big ]$$

But using this pair of Fourier transform how to obtain the $ F \Big\{ f(x) \Big\} $ ?? Is there a direct/simple way to do that?

How can I find the Fourier transform of

$$ f(x) = ( \cos(x) )^3$$

I know that for $ g(x) = \cos(x) $

$$ F \Big\{ g(x) \Big\} = F \Big\{ \cos(x) \Big\} = \pi \Big [ \delta(w-\pi / 2) + \delta(w+\pi / 2) \Big ]$$

But using this pair of Fourier transform how to obtain the $ F \Big\{ f(x) \Big\} $ ?? Is there a direct/simple way to do that?