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Timeline for Why is the FFT "mirrored"?

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S Nov 21, 2023 at 16:41 history edited lennon310 CC BY-SA 4.0
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S Nov 21, 2023 at 16:41 history suggested Rodrigo de Azevedo
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Nov 21, 2023 at 16:23 review Suggested edits
S Nov 21, 2023 at 16:41
Oct 31, 2012 at 18:31 comment added Dilip Sarwate What concerns me a bit is that the two bins have magnitudes $50.6665$ and $50.2971$. Theoretically, they should have equal magnitude $50.5$ as you say, but the difference is a little larger than I feel is attributable to round-off error. Could you re-run your program and tell us what the actual complex values are in those two bins? (Theoretically, the two bin values should be complex conjugates with imaginary parts close to $\pm 50.5$ and small real parts).
Oct 30, 2012 at 19:15 history edited Dilip Sarwate
changed tag to dft since the question has nothing to do with the fft
Oct 29, 2012 at 21:38 answer added Dilip Sarwate timeline score: 31
Oct 29, 2012 at 0:03 history tweeted twitter.com/#!/StackSignals/status/262706130994753536
Oct 28, 2012 at 20:46 answer added hotpaw2 timeline score: 21
Oct 28, 2012 at 20:34 answer added Jim Clay timeline score: 52
Oct 28, 2012 at 19:55 comment added endolith Because a Fourier transform breaks up a signal into complex exponentials, and a sine wave is the sum of 2 complex exponentials. dsp.stackexchange.com/a/449/29
Oct 28, 2012 at 18:21 comment added pichenettes Ask yourself: what result would you expect if your signal was 1 + cos(2*pit)... And 1 + i cos(2*pit)... And 1 + i sin(2*pi*t)...
Oct 28, 2012 at 18:02 comment added WebMonster For a pure real signals F(k)=conj(F(N-k)), this is why the Fourier transform of a pure real signal is symmetric.
Oct 28, 2012 at 17:44 comment added bobobobo But this is specifically about the symmetry (I believe it's called Hermetian symmetry?) of the signal.
Oct 28, 2012 at 17:35 comment added pichenettes A similar question has been answered here: dsp.stackexchange.com/questions/3466/…
Oct 28, 2012 at 16:37 history asked bobobobo CC BY-SA 3.0