2018
Oct
15
awarded  Scholar
Oct
15
comment Conversion between DTFT in radians/sample to DTFT in cycles/sample
Thanks, it was the division by $2 \pi $ that was throwing me off. Perfect answer.
Oct
15
accepted Conversion between DTFT in radians/sample to DTFT in cycles/sample
Oct
15
comment Relationship between the IDFT of a sampled DTFT and its discrete-time domain signal
But what is the math behind this fact, to me it is not obvious why there is aliasing in the discrete time domain.
Oct
15
asked Conversion between DTFT in radians/sample to DTFT in cycles/sample
Oct
15
comment Relationship between the IDFT of a sampled DTFT and its discrete-time domain signal
Correct, I am expecting aliasing in y[n], but I am trying to figure out how to prove derive the expression which relates the aliased $\tilde{s}[m,n]$ values to those of the original signal.
Oct
14
awarded  Student
Oct
14
asked Relationship between the IDFT of a sampled DTFT and its discrete-time domain signal