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Because $Tf{_s}$=1 and $N$ and $n$ are integers. So the exponent becomes 2$\pi$ times an integer, say $K$. But $e{^{i\theta}} = \cos(\theta)+i\sin(\theta)$. Therefore $e{^{i2K\pi}} = 1$.

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I got the answer from a friend through discussion. Actually, symbol error rate is independent of code used but the bit error rate will be different depending on the coding scheme used. I was saying ...

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For any LTI (Linear Time Invariant) system (considering the steady state response i.e. ignoring the transient response which generally becomes negligible in a very short period), if the input is a ...

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In image compression, when the number of bits per pixel are reduced, you might see an artifact called contouring. Dithering is used to reduce this artifact. For more information, please see http:/...

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An LTI system can be completely described by its impulse response. That means, the output of this system can be calculated for any input, once you are given the output of this LTI system to the ...

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Let us first see the theory. By pulse train I guess you mean a periodic function from minus infinity to plus infinity. Your pulse train will have the Fourier series(FS) in stead of Fourier transform(...

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You can take the samples of the speech satisfying Nyquist criterion. Say you got a vector of samples called x. spectrogram(x) would give you the short time Fourier Transform of x. fft(x) would give ...

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The signal can not be reconstructed because in the new sampled signal the sampling theorem is violated. Aliasing would occur and the signal reconstructed would be a lower frequency than the original ...

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Fourier transform of a system is its transfer function and gives the multiplication factor when $e^{j\omega t}$ is the input. $\omega$ is frequency. If you consider the input as current, the ...