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It describes a SIMO (single input, multiple outputs) system. In your case you have two outputs, described by the two different numerator polynomials.


So who is right? Both, I think. On first looks version [3] and version [4] use different definitions of $A(z)$. [3] conjugates the zeros and [4] conjugates the poles. Either one will probably work but the definition of the coefficients is different. Specifically the $a$ coefficients of version [4] or conjugates of those of version [3]. So you have $$a_{n,i,...


Since I gave you a wrong hint first, let me try to make it up. You have the correct transfer function and the rest is (I think) just to slog through the algebra. Here is an outline how this can be approached. We can use the geometric sum property to simply things a bit $$4\cdot H(\omega) = 1 + e^{-j\omega} + e^{-j2\omega} e^{-j2\omega} = \frac{1-e^{-4j\...

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