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Hot answers tagged reconstruction

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Shannon interpolation formula for downsampled data with an "almost ideal" low pass filter

I don't get your downsample step when you downsampled by factor $M$. Let me go from scratch with the spectrum visualization below, with time domain, continuous frequency domain and discrete frequency ...
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Proving Nyquist Sampling Theorem for Strictly Band Limited Signals (Whittaker Shannon Interpolation Formula)

Approaching The Sampling Theorem as Inner Product Space Preface There are many ways to derive the Nyquist Shannon Sampling Theorem with the constraint on the sampling frequency being 2 times the ...
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optimization of Image Reconstruction Algorithm using Genetic Algorithm in Matlab

One simple approach would be taking the mean square error (MSE) by using fitness_1 = mean((inputimage(:) - reconstructedimage_1(:)).^2) though, as your image ...
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What is done to minimize distortion due to the hold operation?

I agree with Jim Clay's answer, but I think it is important to point out two things. First of all, there are no phase distortions due to the hold operation, just a simple delay of half a sampling ...
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What is done to minimize distortion due to the hold operation?

What you are describing is the distortion introduced by an ideal digital-to-analog converter (DAC) in the analog domain. Two things are typically done to reduce this distortion: Analog filtering ...
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Sample and reconstruct a real exponential (just one period)

First, since $t>0$ in your case, you can write your function as $$C(t)=1.6925\left(\exp^{-0.136t}- \exp^{-1.192t} \right) u(t)$$ where $u(t)$ is a unit-step function. ...
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How can a signal have two maximum frequency components?

$x(t)$ must be a band pass signal. Under certain conditions on the sampling frequency and its relation to the lower and upper band edges of the signal, $x(t)$ can be sampled at a frequency that is ...
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Question about MRI signal construction

I would expect that you simply cut the outer parts of the image away. Certainly, there is always a hassle to figure out the proper pixel in the center, but that is a detail of the FT-algorithm ...
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