New answers tagged quadrature
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Maximum Throughput of QAM system
You need to round down the the bits per symbol $M$ to the nearest EVEN integer since rounding up will add more symbols in you constellation and increase error beyond the acceptable limit. So 6 bits ...
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Do all phase quadrature signals form orthogonal pairs with their in-phase versions
It is true that a (real-valued) signal $x(t)$ and its Hilbert transform $\hat{x}(t)$ are orthogonal, i.e.
$$\int_{-\infty}^{\infty}x(t)\hat{x}(t)dt=0\tag{1}$$
This can be shown as follows. First, note ...
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