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Autocorrelating output signal which sampled at rates higher than signalling rate

When sampling at the symbol rate, there is no ISI. The matched filter output for $y(t)$ can be expressed as: $$ y(t) = \sum_{n=0}^{k-1} a_n \int_{-\infty}^{\infty} p(t^{\prime} - nT_s) p^{*}(t^{\prime}...
AHT's user avatar
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3 votes
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DAC - Can we create and use frequencies above Fs/2?

In addition to the good points Marcus has made in his answer, I want to add that there are other DAC topologies specific for doing this more efficiently. The OP is correct that a traditional (Non-...
Dan Boschen's user avatar
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DAC - Can we create and use frequencies above Fs/2?

Yes, in your specific case, quite easily. Your system has no reconstruction filter, or rather, it is just a zero-order-hold output, so essentially the ideal DAC output is square wave steps. Square ...
Justme's user avatar
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3 votes

DAC - Can we create and use frequencies above Fs/2?

DAC - Can we create and use frequencies above Fs/2? yes, that's commonly done. You can work with any image you want, as long as it's pronounced enough (in the end, as long as the analog bandwidth of ...
Marcus Müller's user avatar
2 votes

Methods to determine stability of open-loop systems

It appears you can use a Nyquist plot and just consider encirclements of the origin rather than -1. My reasoning was to follow a similar mathematical derivation to that on the Wikipedia page for the ...
Stephen's user avatar
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Why does twice the sampling rate (Nyquist Theorem) seem inadequate?

"a sine wave with only 2-3 samples per period looks very ugly even though it obeys this rule. It looks more like a triangle wave." This is an old question but I still think it's worth it to ...
cebola's user avatar
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