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The Japanese link actually implies how to derive Eq.5, and ironically they also refer to an existing dsp.se answer at the bottom. Derivation of Eq.5 is as follows: Consider a moving average filter of length $N$, with the impulse response $h[n]$: $$h[n] = \begin{cases} ~~~1/N~~~,~~~n=0,1,...,N-1 \\ ~~~0~~~,~~~ \text{otherwise} \end{cases} \tag{1}$$ Magnitude ...


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The OP is implementing the Hogenauer Filter (thank you Eugene! http://read.pudn.com/downloads163/ebook/744947/123.pdf), also called a CIC Filter, as an efficient equivalent of the moving average filter, and is getting a noise error result that is 10x more than expected. Short Answer The reason for the additional error in the OP's case is due to not having an ...


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