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The number of additions is just the length of the individual vectors times their number minus $1$: $$\textrm{number of additions}=N\cdot\frac{2^l-1}{2^l}$$ Of course we assume that $N$ is a power of $... • 80.2k 3 votes Accepted ### What is the complexity of multiplication a real matrix with real vector If you multiply an$M \times N$matrix with an$N \times 1$vector you get a vector of size$M \times 1$For the generic case you will need$M \cdot N$multiplications and$M \cdot (N-1)$additions. ... • 31.5k 2 votes Accepted ### How can I express the flipped output of multiplication in function of original inputs? You just need to conjugate the matrix$D$as well as the vector$x$, and flip the rows of$D$upside down, i.e., the first row becomes the last row, etc. I.e., you need to introduce a new matrix$\...
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Simple Answer A simple way to solve this is by using diagonal loading (see this answer for a related example). If your square matrix is $R$, then instead of inverting $R$, invert $R + \sigma I$, where ...