New answers tagged

0

hFilt = designfilt('hilbertfir','FilterOrder',n,'TransitionWidth',TW); n is the order of the filter and TW is the transition width. d = fdesign.hilbert b = firpm(n,f,fresp,w,'hilbert') n - order of the filter f - normalized frequency points for transition bandwidth w - weight of the points


1

Two samples is sufficient and we can determine if the phase difference is indeed $\frac{3\pi}{2}$ as follows: Start with the hypothesis that the phase difference $\phi_1-\phi_2$ is $\frac{3\pi}{2}$, which is equivalent to $-\frac{\pi}{2}$ If and only if the phase is in such quadrature, then $s_1(t)$ and $s_2(t)$ will be the real and imaginary components of ...


1

HINT: It looks like they shifted the frequency response by half the sampling frequency, i.e., $$H_{HP}\left(e^{j\omega}\right)=H_{LP}\big(e^{j(\omega-\pi)}\big)\tag{1}$$ Frequency shifting corresponds to modulation (multiplication) in the time domain. Now you just have to figure out the modulation sequence that achieves the correct frequency shift.


Top 50 recent answers are included