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# Tag Info

Say each of the 10 pixel values on a row consists of $N$ bits. An $N$-bit wrap-around-arithmetic sum of the values gives just enough additional information to reconstruct the 10th value from the 9 previous values: subtract the 9-sum from the 10-sum. So 10 values that are needed for reconstruction each row, which is the same as the size of the original data. ...