# Tag Info

1

For the cross correlation of the output of the filter with the input you should see the result of the two impulses in your filter convolved with the cross correlation properties of your actual waveform. If your waveform is random such that there is only a correlation at 0 lag then the result here would be a positive correlation peak at lag zero and then an ...

1

You may be working the wrong problem here: echo data hiding seems like a sub-optimal choice for an acoustic channel (speaker -> microphone). Transmitting data acoustically in a room is very hard. The channel is quite complicated and difficult to deal with: Loudspeakers tend to be very non-flat and have a fair bit of non-linear distortion. Microphones are ...

0

the group delay is D=(N-1)/2=20 samples No. Group delay is a function of frequency. Assigning a single number to group delay is somewhat questionable. While the phase is indeed piece wise linear, at the "dips" of the combfilter, the phase jumps from $-\pi$ /2 to $\pi/2$. This is a real discontinuity, not a wrapping issue. At these frequencies the group ...

4

Since this is an FIR, the group delay is D=(N-1)/2=20 samples. No, since this is a linear phase (i.e. symmetric or anti-symmetric) filter, the group delay is half the length! (being a FIR isn't sufficient.) The issue is that I get too peaks in the cross correlation, one at zero lag and another at 20 lag. Write down the formula for auto-correlation at ...

Top 50 recent answers are included