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I've sampled it at a 1 bit resolution (as 8 bit oscilloscope readings & 0b1) No. Taking the LSB is NOT 1 bit quantization. A one bit quantizers are not trivial to design. For a zero mean signal that's reasonably symmetrically distributed over positive and negative values, you can just take the sign bit. For signals that are asymmetrically distributed ...


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You can use corrcoef to compute the Correlation coefficients as a measure of linear dependence of the random vectors (i.e you transpose your row vectors, the variables are column vectors, and the rows are observations). With the vectors u = [1, 2, 3, 4]; v1 = [10, 10, 10, 10]; v2 = [0, 1, 2, 3]; You have >> R = corrcoef([u', v1', v2']) R = 1 ...


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