I've sampled it at a 1 bit resolution (as 8 bit oscilloscope readings & 0b1)
No. Taking the LSB is NOT 1 bit quantization. A one bit quantizers are not trivial to design. For a zero mean signal that's reasonably symmetrically distributed over positive and negative values, you can just take the sign bit. For signals that are asymmetrically distributed ...
You can use corrcoef to compute the Correlation coefficients as a measure of linear dependence of the random vectors (i.e you transpose your row vectors, the variables are column vectors, and the rows are observations). With the vectors
u = [1, 2, 3, 4];
v1 = [10, 10, 10, 10];
v2 = [0, 1, 2, 3];
>> R = corrcoef([u', v1', v2'])