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Lets say you have a continuous sinusoidal signal $x(t) = \cos(2\pi f_o t)$, now we sample that signal by letting $t=nT=\frac{n}{f_s}$, where $f_s$ is the sampling frequency. This gives $x[n]= \cos(2\p …
answered Feb 6 '15 by David
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Assume the original sampling rate is $F_s$ and that the filters are perfect brickwall Halfband filters. After the low pass filtering the frequency content is from $0 \rightarrow \frac{F_s}{4}$. Becaus …
answered Jun 20 by David