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user 32826
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Convolution and Modulation Theorem with Octave Example
As far as I know, convolution theorem stated that
$$
x[n] * y[n] = X(e^{j \omega}) Y(e^{j \omega})
$$
$$
X(e^{j \omega}) * Y(e^{j \omega}) = x[n] y[n]
$$
I tried a simple experiment using GNU Octave …
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