I'm trying to understand how I can start from the CTFT of a signal and end up with a DTFT.

For example if I take a basic example:
$$
x(t) = cos(\omega_x \cdot t) = \frac{1}{2} \cdot \left( e^{j\omega_x t} + e^{j\omega_x t} \right)
$$
$$
\implies X(\omega) = \pi \cdot (\delta(\omega - \omega_x) + \delta(\omega+\omega_x))
$$
$$
x_c(t) = x(t) \cdot \sum_{n=-\infty}^{\infty}\delta(t - nT_s) = \sum_{n=-\infty}^{\infty}x(nT_s)\delta(t-nT_s)
$$

$$
\implies X_c(\omega) = X(\omega) * \left( \omega_s \sum_{n=-\infty}^{\infty} \delta(\omega - n\omega_s)\right)
$$
$$ X_c(\omega) = \omega_s \pi \sum_{n=-\infty}^{\infty} \left(  \delta(\omega - \omega_x - n\omega_s) +  \delta(\omega + \omega_x - n\omega_s) \right)
\tag{1}
\label{1}
$$

From there I'm lost and everything crumbles. I'm only trying to get the DTFT of a cosine which is:
$$
cos(\Omega_0 n) \Leftrightarrow \pi \sum_{n=-\infty}^{\infty} \left(  \delta(\Omega - \Omega_0 - n2\pi) +  \delta(\Omega + \Omega_0 - n2\pi) \right)
\tag{2}
\label{2}
$$

How can I obtain $\eqref{2}$ starting from $\eqref{1}$?
I hope what I'm trying even makes sense. After all the DTFT with infinite period is the CTFT so I suppose there's a link we can make between these equations?

Thanks