I am restating the question using standard EE DSP notation as we might find in O&S (and correcting errors regarding spurious appearance of $2 \pi$):
Suppose a discrete-time, finite power signal
$$x[n] \triangleq x(n/f_\mathrm{s}) \qquad \qquad \text{(where } x(t) \text{ is the continuous-time signal being sampled)}$$
has power spectral density
$$
S_{x}(f) = \lim_{N\to \infty}\mathbb{E}\left[\frac{1}{N}\left| \sum\limits_{n=-N/2}^{N/2-1} x[n] e^{-j 2 \pi n f/f_\mathrm{s}} \right|^2 \right]
$$
where $f_\mathrm{s}$ is the frequency of an "ideal" clock (the sample rate) so that the rising edge of the clock occurs at $t_n = n/f_\mathrm{s} + x[n]$ (...this expression makes no sense).
Suppose we can only draw $M$ samples from the infinite sequence. How fast does the quantity
$$
S_{x}^{(M)}(f) = \mathbb{E}\left[\frac{1}{M}\left| \sum\limits_{n=-M/2}^{M/2-1} x[n] e^{-j 2 \pi n f/f_\mathrm{s}} \right|^2 \right]
$$
converge to $S_{x}(f)$? Can general statements be made? (If general statements cannot be made, I am content with results restricted to sequences that are roughly flicker.)
The next thing that the OP should realize is the standard definition of the Discrete-Time Fourier Transform (DTFT):
$$ X\big(e^{j\omega}\big) \triangleq \sum\limits_{n=-\infty}^{\infty} x[n] e^{-j \omega n} $$
Which defines the normalized angular frequency $\omega$ in terms of continuous-time frequency $f$ as
$$ \omega \triangleq 2 \pi \frac{f}{f_\mathrm{s}} $$
THAT is "standard notation" in the DSP subdiscipline within the electrical engineering discipline.