Almost all of the searches online have returned results related to image-processing, but I am looking for a more rudimentary example with some physical intuition (eg; a high-pass filter only lets the high frequency components pass, thus filtering out the low frequency components).

The specific filter that I found and am wanting to understand is:

$$g(t) = \sin\left(\frac{2 \pi t}{\lambda} + \phi\right)\exp\left(\frac{-t^2}{2 \sigma^2}\right)$$

  1. Is this a general expression? Would it matter if I used $\cos$ instead of $\sin$?

  2. What would the O/P look like if I applied the above 1D Gabor filters to a sinusoid? I am not exactly sure what a good sinusoid would be to demonstrate this, but I am guessing a simple sine/cosine won't suffice, since it has a single frequency?

  3. How would changing the values of $\lambda$, $\sigma$, $\phi$ affect the O/P?

  • $\begingroup$ It filters out frequencies that are not particularly close to $f=\frac{1}{\lambda}$. $\endgroup$ Commented Sep 8, 2023 at 21:47

1 Answer 1


Multiplication in time-domain is convolution in Fourier domain. You have $\mathscr{F}\{\sin\}$ (assuming $\phi=0$) which is two Dirac-Delta impulses in the Fourier domain. The FT of a Gaussian (the exponential term) is also a Gaussian, proof.

So, in the Fourier domain you have a Gaussian convolved with two shifted impulses which will just place the Gaussian at those impulses. With that out of the way here are answers to your specific questions:

  1. $\cos$ and $\sin$ have slightly different Fourier Transforms: $$\cos(2 \pi f_0 t)\overset{\mathscr{F}}{\longleftrightarrow}\tfrac12\big(\delta(f-f_{0})+\delta(f+f_{0})\big)$$ and $$\sin(2 \pi f_0 t)\overset{\mathscr{F}}{\longleftrightarrow}\tfrac1{2j}\big(\delta(f-f_{0})-\delta(f+f_{0})\big)$$

  2. Depends at which frequency your sinusoidal is. You can use a chirp to test it.

  3. $\lambda$ controls the frequency of your $\sin$, which determines the resonant frequency of the filter, $\phi$ changes the phase shift which adds an exponential term (magnitude only) in the Fourier Domain (verify this by writing the sinusoidal in terms of complex exponentials). $\sigma$ controls the width of your Gaussian. It is the variance. Essentially, changing these parameters changes the shape of your filter which will lead to filtering (attenuating) different frequencies depending on the shape.

  • $\begingroup$ First question related to your first paragraph - I can have an LTI I/P signal, convolve it with the Gabor filter and get the O/P - all in the time domain itself. Where does the FT and frequency domain come into the picture? Maybe you were trying to explain something that I didn't grasp. That aside, my understanding based on some more reading is that the O/P will have frequencies close to $\lambda$, and also show exactly when they happened. I still don't understand the importance of the $\sigma$ - is it like a window that needs to be larger than the $\lambda$? $\endgroup$
    – SNIreaPER
    Commented Sep 9, 2023 at 0:17
  • $\begingroup$ Following up on this - can you explain what the $\lambda$ is useful for? $\endgroup$
    – SNIreaPER
    Commented Mar 1 at 5:57
  • $\begingroup$ @SNIreaPER It is useful for selecting the frequencies of interest. $\endgroup$ Commented Mar 5 at 8:31
  • $\begingroup$ my bad - I meant to ask what is the significance of \sigma $\endgroup$
    – SNIreaPER
    Commented Mar 5 at 17:15
  • 1
    $\begingroup$ @SNIreaPER Does this desmos plot help? $\endgroup$ Commented Mar 5 at 17:40

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.