The quickest way would be
[b,a] = ellip(8,1.5,60,[.2 .3]);
This designs a bandpass from .2 to .3 with 1.5 dB ripple and 60 db stop band attenuation. You don't get to pick the edges of the stop band since you already pre-selected the order. You can do one or the other but not both at the same time. However the 8th order filter is more than enough to meet your stop band requirements. In fact the low band stops at 0.195 and the high stop band starts at 0.307.
Another wrinkle is that the ripple actually only goes down, i.e. passband is not between -1.5dB and +1.5 dB but only between -1.5dB and 0 dB. In order to work aound this (if you care) you can double the ripple to 3 dB and than simply add 1.5 dB gain. You would also have to increase the stop band attenuation to 61.5dB to compensate for the overall gain change. The funcion $ellipord$ allows to calculate the required order to achieve a certain stop band, so the correctest way would be
%% Ellip filter design example
[n,wp] = ellipord([.2 .3],[.14 .36],3,61.5);
[b,a] = ellip(n,3,61.5,wp);
% add 1.5 dB of gain
b = b*10.^(1.5/20);
[H,F]= freqz(b,a,1000,2);
plot(F,10*log10(H.*conj(H)));
set(gca,'ylim',[-70,3]);
grid('on');
So it turns out a 5th order elliptic filter can do the job just fine.