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Using the following website: on how the Fourier transform works (Interested in the Basic Principle part). I found out that if you have 3 pixels closer in the spatial domain you'll get more spaced fringes in the Fourier domain (frequency domain). How could one explain this ?

Also I don't understand why our 3 closer points would have a lower spacial frequency ? If they're closer then the distance ($\lambda$) separating them is lesser thus the frequency ($\propto \frac{1}{\lambda}$) is greater ?

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  • $\begingroup$ "spatial domain" and "frequency domain" are correct $\endgroup$
    – endolith
    Apr 10, 2022 at 22:06

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Also I don't understand why our 3 closer points would have a lower spacial frequency ?

Wider spaced fringes or points in the Fourier domain means a higher frequency, not a lower frequency. They are spaced further away from 0, which means they are higher in value. The further away from the center in the frequency domain, the higher the frequency.

If they're closer then the distance (λ) separating them is lesser thus the frequency (∝1λ) is greater ?

Yes

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  • $\begingroup$ Ok I See ! Trank you ! $\endgroup$
    – Michael
    Apr 12, 2022 at 5:33

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