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$\Omega_c$=cutoff analog frequency

In this example, what is going to be value of $\Omega_c$?

Question

Some teachers in youtube are teaching this method:

$\Omega_c = ?$

$H(s) = \frac{\Omega_c}{(s-s_1)(s-s_2)(s-s_3)}$

Other people are doing this

$H(s) = \frac{N(s)}{D(s)}$

$N(s) = \left.\frac{D(s)}{\sqrt{1+\varepsilon^2}}\right|_{s=0}$ for even N

$N(s) = \left.D(s)\right|_{s=0}$ for odd N

Is this method correct?

$$\Omega_c = \frac{\Omega_p}{\left(\frac{1}{A_p^2}-1\right)^{1/2N}}$$

If I use this formula, then I get infinite analog cut off frequency. So, I don't think this is correct.

I am really confused in how to calculate cut off frequency. How do I calculate it?

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  • $\begingroup$ I have converted the images of calculations to MathJax. (Edit may be pending) Please check that I did so correctly and consider using MathJax in the future. $\endgroup$ Feb 12 at 21:56

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