# Finding transfer function from bode plot

Given a bode diagram

From the figure, I see that when $$\omega = 100 \text{ rad/s}$$ the magnitude response starting to go down and when $$\omega = 1000 \text{ rad/s}$$ the slope become higher. Then

$$H(s) = \frac{1}{\left(\frac{s}{100} + 1 \right)\left(\frac{s}{1000} + 1 \right)}$$

Then I tried to plot it on MatLab and here's what I got

The plot shape is close but both Y-axis are different. Where did I go wrong?

Looking at both phase and level we conclude that it's a first order lowpass with $$f_c = 1000 rad/s$$, hence the whole thing is simply
$$H(s) = \frac{1}{\frac{s}{1000}+1}$$