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check time variance of this system $$y (t) = x(\frac{t}{3})$$

my solution $$y_1(t) = x_1(t/3)\\ y_2(t) = x_2(t)= x_1(\dfrac{t}{3}-t_o)$$ where $$ x_2(t) = x_1(t-t_o)\\ y_1(t - t_o) = x_1(\dfrac{t-t_o}{3}) \ne y_2(t)$$ is this correct?

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  • $\begingroup$ Looks good. You applied the test of time invariance and got the right answer! $\endgroup$
    – Hilmar
    Commented May 26, 2021 at 0:44

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