# Can the DFT can be performed without normalization?

If we have OFDM system with $$N$$ sub-carriers, the DFT matrix can be expressed as follows:

$$F = dfmtx(N)/sqrt(N)$$

My question, is it possible and practical to use the matrix without Normalization, it means use the iDFT as $$F = (dfmtx(N))'$$, and then at the receiver end, I will multiply with that matrix and divided by $$N$$ (like this $$dfmtx(N)/N)$$ to get scalar diagonal matrix whose diagonal elements are 1?

thank you

Yes. In fact, depending on your receiver architecture, you may not need the divide by $$N$$ in the receiver.
• OK thank you, but about your saying "depending on your receiver architecture, you may not need the divide by NN in the receiver." ,But, if I didn't divide by $N$, it means that $(dfmtx(N))′*(dfmtx(N))$ is a scalar diagonal matrix with diagonal elements equal to $N$ which won't be able to detect the modulated elements. – Fatima_Ali Mar 1 at 5:11