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I have defined the following linear phase filter of order 4 (real and symmetric) in matlab: h_d = [0.8367 -1.537 1 -1.537 0.8367] I calculate the frequency response (for many points) and then I use firls function (which is supposed to give the least-squares solution) to find a linear phase FIR filter (5 taps) that matches the desired response. However the filter is nowhere close to h_d. What am I doing wrong? Here is the code:

f = [0:1/(2^14-1):1];
[a,~] = freqz([0.8367 -1.537 1 -1.537 0.8367],1,f*pi);
a=abs(a);
n = 4; % Filter order
b_lp = firls(n,f,a);
[h,w] = freqz(b_lp,1,512);
figure(1)
plot(f,20*log10(abs(a)),'-s')
hold on
plot(w/pi,20*log10(abs(h)))

I appreciate any insights.

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The function firls() is meant to design filters with piecewise constant magnitude responses. So in practice you use only a few frequency points and the corresponding desired magnitude values, and the function computes a linear interpolation between the given frequency points. Of course, in theory your call to firls is correct, but I guess that the resulting system of linear equations becomes ill-conditioned.

I wrote a function lslevin.m, which can be used in the way you intended to use firls:

h = [0.8367 -1.537 1 -1.537 0.8367];
[H,w] = freqz(h,1,2048);    % that's more than enough frequency points
h2 = lslevin(5,w,H,ones(size(H)));
[H2,w] = freqz(h2,1,2048);
plot(w/pi,abs(H),w/pi,abs(H2),'r--')
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  • $\begingroup$ Awesome, thanks a lot for your help. $\endgroup$ Dec 2 '20 at 15:05

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