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Given $X(v)$ the Discrete Fourier transform of a discrete periodic signal $x(n)$, it's possible to arrive to the $c_k$ of the Fourier series $$x(n)=\sum_{k=0}^{n-1} c_k \exp(2\pi i k t) $$ directly?

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  • $\begingroup$ um, write down the formula of the IDFT directly below your formula, i.e. how $x(n)$ can be calculated from $X(k)$. What do you notice? $\endgroup$ Nov 27 '20 at 11:01
  • $\begingroup$ what's the IDFT ? @MarcusMüller $\endgroup$ Nov 27 '20 at 17:04
  • $\begingroup$ The inverse discrete Fourier transform; wikipedia! $\endgroup$ Nov 27 '20 at 17:28

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