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I am about to understand a kurtogram, and don't understand what means the value of "K" (presented in table 1),or especially why takes values of 1.6 ; 2.6 ; 3.6 etc. Other question is how do interpret the kurtogram (figure 2)

table and figure kutogram

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  • $\begingroup$ I have updated with hints. I would suggest you to read several papers, especially the early ones, showing interpretations of different kurtograms. $\endgroup$ Commented Nov 10, 2020 at 6:27
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    $\begingroup$ If the answer below is helpful, please accept it by clicking on the green check mark, thanks! $\endgroup$
    – Matt L.
    Commented Nov 10, 2020 at 10:15

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[Given figures are from A new improved Kurtogram and its application to planetary gearbox degradation feature analysis, Xianglong Ni et al.]

This $k$ in the graph (and the $K$ in the Table) corresponds to an equivalent "dyadic-power", providing the number of subsequences at each level, alternating dyadic splits with filters on subbands $[0,1/4]/[1/4,1/2]$ and $[0,1/6]/[1/6,1/3]/[1/3,1/2]$. The number of such subsequences in the 1/3-binary tree are $2,3,4,6,8,12\ldots$, approximately $2^1,2^{1.6},2^{2},2^{2.6},2^3,2^{3.6}\ldots$, since $\log(2)/\log(3)\sim 0.6$.

Additional sources:

I unfortunately cannot help totally on the interpretation of this particular paper. I remember that the original spectral kurtogram was meant to detect, localize or characterize nonstationarities from signals. The kurtogram was a fast version, reusing principles from wavelet packets and multiband filter banks and quasi-analytic filters. When looking at maximum values in a kurtogram, if they are concentrated, one may suspect non-stationary components in a noisy signal. Then, it is possible to extract or invert the aforementioned component to check or denoise the original data. I would suggest you to read several papers, especially the early ones, showing interpretations of different kurtograms.

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    $\begingroup$ your answer is most helpful thank you so much $\endgroup$
    – RIMA
    Commented Nov 9, 2020 at 22:33
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This will be helpful for You to interpret kurtogram https://www.mathworks.com/help/predmaint/ug/Rolling-Element-Bearing-Fault-Diagnosis.html

enter image description here

If we look on the results the most important elements are:

Kmax = 2.7083 - is maximum value or kurtosis

Optimal Window Length = 128 - this value we can use to calculate spectral kurtosis

Center Frequency = 2.6703 kHz and Bandwidttch = 0.76294 kHz - this two parmateres we can use do design band pass filter

The kurtogram is used in bearing fault diagnosis to extract the most impulsive signal from the signal. Base on this example we can say: if we select center frequency = 2.6703 kHz and bandwidth = 0.76294 kHz we can obtain a signal after filtration that gives the most impulsive characteristic. Using these parmaters we can calculate the envelope spectrum for the final diagnostic.

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    $\begingroup$ Hi! Link-only answers are not very well-received here, as they depend on external sources instead of answering the question themselves. Maybe a short synopsis of what you're linking to would improve this answer! $\endgroup$ Commented Nov 10, 2020 at 19:58
  • $\begingroup$ Thank you for your answer I appreciate it $\endgroup$
    – RIMA
    Commented Nov 11, 2020 at 21:23

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