1
$\begingroup$

Hi I'm trying to solve the problem when studying for an upcoming test.

The given solution is $1.2503 e^{jnπ/4 -0.2991}$, and is found by computing $H(Ω)$ and evaluating this at $Ω=π/4$. when I try this I get $H(π/4)=(1/3)^8=0.000152$ and therefore the convolution is $0.000152e^{jnπ/4}$.

I'm not sure where I'm going wrong so any help would be appreciated so much!

$\endgroup$
2
  • $\begingroup$ You should first find the DTFT $H(\omega)$ of $h[n]$, then evaluate $H(\pi/4)$... $\endgroup$
    – Fat32
    Oct 31 '20 at 19:05
  • 1
    $\begingroup$ You should really explain how you evaluated $H(\pi/4)$ ... $\endgroup$
    – Matt L.
    Nov 1 '20 at 8:41

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.